15x^2+32x=-16

Solution for 15x^2+32x=-16 equation:

15x^2+32x=-16

We move all terms to the left:

15x^2+32x-(-16)=0

We add all the numbers together, and all the variables

15x^2+32x+16=0

a = 15; b = 32; c = +16;
Δ = b2-4ac
Δ = 322-4·15·16
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-8}{2*15}=\frac{-40}{30}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+8}{2*15}=\frac{-24}{30}
=-4/5
$